Using file upload in Liferay with Struts Portlet

[Akira Akira, módosítva 12 év-val korábban]

File jsp

<%@page language="java" contentType="text/html; charset=UTF-8" pageEncoding="UTF-8"%>

<form name="<portlet:namespace />fm" method="post" enctype="multipart/form-data" action="<portlet:actionURL windowState=" <%="WindowState.NORMAL.toString()" %>"&gt;<portlet:param name="struts_action" value="/ext/upload/uploadimage" />"&gt;

   <table border="2">
       <tbody><tr>
               <td align="center"><b> upload file </b></td>
       </tr>
       
       <tr>
               <td>
                      Choise 1: <input name="file" type="file" id="file">
               </td>
               <td><input type="submit" name="Submit" value="Submit"></td>
       </tr>          
    </tbody></table>
</form>

file .java

import java.io.File;
import java.util.Iterator;
import java.util.List;
import java.util.Random;
import java.util.regex.Matcher;
import java.util.regex.Pattern;

import javax.portlet.ActionRequest;
import javax.portlet.ActionResponse;
import javax.portlet.PortletConfig;
import javax.portlet.RenderRequest;
import javax.portlet.RenderResponse;

import org.apache.commons.fileupload.FileItem;
import org.apache.commons.fileupload.FileItemFactory;
import org.apache.commons.fileupload.FileUploadException;
import org.apache.commons.fileupload.disk.DiskFileItemFactory;
import org.apache.commons.fileupload.portlet.PortletFileUpload;
import org.apache.struts.action.ActionForm;
import org.apache.struts.action.ActionForward;
import org.apache.struts.action.ActionMapping;

import com.liferay.portal.struts.PortletAction;

public class ActionUpload extends PortletAction {
	public void processAction(ActionMapping mapping, ActionForm form,
			PortletConfig config, ActionRequest req, ActionResponse res)
			throws Exception {
			System.out.println("Process upload");
			boolean isMultipart =PortletFileUpload.isMultipartContent(req);
			System.out.println("request: "+req);
			if (!isMultipart) {
				  System.out.println("File Not Uploaded");
			}else {
				FileItemFactory factory = new DiskFileItemFactory();
				PortletFileUpload upload = new PortletFileUpload(factory);
				List items = null;
				try {
					  items = upload.parseRequest(req);
					 [color=#e43a3a] System.out.println("items: "+items);[/color]
				} catch (FileUploadException e) {
					  e.printStackTrace();
				}
				Iterator itr = items.iterator();
				  while (itr.hasNext()) {
				  FileItem item = (FileItem) itr.next();
				  if (item.isFormField()){
				  String name = item.getFieldName();
				  System.out.println("name: "+name);
				  String value = item.getString();
				  System.out.println("value: "+value);
				  } else {
					  try {
						  String itemName = item.getName();
						  Random generator = new Random();
						  int r = Math.abs(generator.nextInt());

						  String reg = "[.*]";
						  String replacingtext = "";
						  System.out.println("Text before replacing is:-" + itemName);
						  Pattern pattern = Pattern.compile(reg);
						  Matcher matcher = pattern.matcher(itemName);
						  StringBuffer buffer = new StringBuffer();

						  while (matcher.find()) {
							  matcher.appendReplacement(buffer, replacingtext);
						  }
						  int IndexOf = itemName.indexOf("."); 
						  String domainName = itemName.substring(IndexOf);
						  System.out.println("domainName: "+domainName);

						  String finalimage = buffer.toString()+"_"+r+domainName;
						  System.out.println("Final Image==="+finalimage);
						  File savedFile = new File(config.getPortletContext().getRealPath("/")+"uploadedFiles/"+itemName);
						  item.write(savedFile);
					  	}catch (Exception e) {
					  		System.out.println(e.getMessage());
					  	}		
				  	}
				}
			}
	        
	}
	
	public ActionForward render(ActionMapping mapping, ActionForm form,
			PortletConfig portletConfig, RenderRequest renderRequest,
			RenderResponse renderResponse) throws Exception{
		return mapping.findForward("ext.upload.view");
	}
	
	
}

When I run out:

request: com.liferay.portal.upload.UploadPortletRequestImpl@53678
items: [] ??????

Can who help me ?

[Anil Sunkari, módosítva 12 év-val korábban]

Hi Akira,

Try to get the request like this


UploadPortletRequest uploadRequest = PortalUtil.getUploadPortletRequest(actionRequest);

if (uploadRequest != null) {

String xxxFileName = uploadRequest.getFileName("file");
File xxFile = uploadRequest.getFile("file");
}

Hope it helps!

Regards,
Anil Sunkari

[Akira Akira, módosítva 12 év-val korábban]

Thanks Anil Sunkari for answer .

How I save "file" to path config.getPortletContext().getRealPath("/")+"uploadedFiles/"

I run :

public class ActionUpload extends PortletAction {
	public void processAction(ActionMapping mapping, ActionForm form,
			PortletConfig config, ActionRequest req, ActionResponse res)
			throws Exception {
			UploadPortletRequest uploadRequest = PortalUtil.getUploadPortletRequest(req);

			if (uploadRequest != null) {

				String xxxFileName = uploadRequest.getFileName("file");
				File xxFile = uploadRequest.getFile("file");
				
				System.out.println("xxxFileName" + xxxFileName );
				System.out.println("xxxFile" + xxFile);
			}
	        
	}

out:

xxxFileName
xxxFileE:\trunk\tomcat\temp\upload_00000000
xxxFileName
xxxFileE:\trunk\tomcat\temp\upload_00000002

name image change ???

String xxxFileName no data.

[Akira Akira, módosítva 12 év-val korábban]

I want upload a image to server liferay.
Can who help me ?

[Mani kandan, módosítva 12 év-val korábban]

For storing a file you should include,

          String realPath = getPortletContext().getRealPath("/");
          String sourceFileName =uploadRequest.getFileName("fileName");
          File file = uploadRequest.getFile("fileName");
          File newFile=null;
          newFile = new File(realPath+"html/portlet"+sourceFileName);
          FileInputStream fileInputStream = new FileInputStream(file);
          FileOutputStream fileOutputStream = new FileOutputStream(newFile);
          fileOutputStream.close();
          fileInputStream.close();

After uploading the file you can find you file inside tomcat/webapps/ROOT/html/portlet

To get the source code link

[Akira Akira, módosítva 12 év-val korábban]

Thanks Mani kandan

I success but name file image change.

UploadPortletRequest uploadRequest = PortalUtil.getUploadPortletRequest(req);
			
			File xxFile = uploadRequest.getFile("file");	
			
			String dirFileSave = config.getPortletContext().getRealPath("/")+"uploadedFiles/"+xxFile.getName();
				
				try
				{
					byte[] bytes = FileUtil.getBytes(xxFile);
		
					if ((bytes == null) || (bytes.length == 0)) 
					{
						dirFileSave = null;
					}
					
					if(FileUtil.exists(dirFileSave)) 
						
						FileUtil.delete(dirFileSave);
					
					File saveTo = new File(dirFileSave);
					
					FileUtil.write(saveTo, bytes);
				}
				catch (Exception e)
				{
			    	  System.out.print(e.toString());
			    	  dirFileSave = null;
			    }			

[Mani kandan, módosítva 12 év-val korábban]

I couldn't understand, Which one is changing?
Better you list out your error or example

[Akira Akira, módosítva 12 év-val korábban]

when I submit path image "C:\Users\Skiatt\Desktop\buy1009\22.jpg""

>>> name image change >> C:\Users\Skiatt\Desktop\buy1009\upload_00000006.jpg

???????????

UploadPortletRequest uploadRequest = PortalUtil.getUploadPortletRequest(req);
			File xxFile = uploadRequest.getFile("file");	
			[color=#e20f0f]System.out.println(xxFile.getName());
			System.out.println(xxFile.getPath());[/color]
			String dirFileSave = config.getPortletContext().getRealPath("/")+"uploadedFiles/"+xxFile.getName();
						
				try
				{
					byte[] bytes = FileUtil.getBytes(xxFile);
		
					if ((bytes == null) || (bytes.length == 0)) 
					{
						dirFileSave = null;
					}
					
					if(FileUtil.exists(dirFileSave)) 
						
					FileUtil.delete(dirFileSave);
					
					File saveTo = new File(dirFileSave);
					
					FileUtil.write(saveTo, bytes);
				}
				catch (Exception e)
				{
			    	  System.out.print(e.toString());
			    	  dirFileSave = null;
			    }			

[Mani kandan, módosítva 12 év-val korábban]

See this is my ProcessAction method, I can able to upload the file without changing the file name.

		public void processAction(ActionRequest request, ActionResponse response) throws PortletException, IOException
		{  

			String realPath = getPortletContext().getRealPath("/");
			byte[] bytes = null;
	
			try{ 
				
			    UploadPortletRequest uploadRequest = PortalUtil.getUploadPortletRequest(request);
			    String sourceFileName =uploadRequest.getFileName("fileName");
				File file = uploadRequest.getFile("fileName");
				try {
					bytes = FileUtil.getBytes(file);
				} catch (IOException e2) {			
					e2.printStackTrace();
				}
				File newFile=null;
				
				if ((bytes != null) && (bytes.length > 0)) {
				
				try {
				newFile = new File(realPath+"html/portlet/"+sourceFileName);
				FileInputStream fileInputStream = new FileInputStream(file);
				FileOutputStream fileOutputStream = new FileOutputStream(newFile);			
				fileInputStream.read(bytes);				
				fileOutputStream.write(bytes, 0, bytes.length);					
				fileOutputStream.close();
				fileInputStream.close();
			} 
				catch (FileNotFoundException e) {
					System.out.println("File Not Found.");				
					e.printStackTrace();
				}
				catch (IOException e1){
					System.out.println("Error Reading The File.");
					e1.printStackTrace();
				}
			}
	}

[Akira Akira, módosítva 12 év-val korábban]

thanks Mani kandan

use

String sourceFileName =uploadRequest.getFileName("fileName");

Good source code

[Mani kandan, módosítva 12 év-val korábban]

You welcome

[Satish Babu Anupoju, módosítva 11 év-val korábban]

Hi Mani

Can you please give me some suggestions . Below you can find the issue :

As per my requirement I have to create Parent folder( Doctor) under that multiple sub folders like (Physician, Dermitologist) under specific sub folders I have to upload image. that should be implement programatically.

I have done the implementation. Parent and first sub folder creating successfully. When I am creating another sub folder (Dynamically) it is throwing exception : DuplicateFolderNameException. I am passing the Folder name dynamically. So there is no chance to getting the duplicate name.

I hope you understand my requirement.

Below you can find the code :
JSP :
===
<portlet:actionURL var="fileUploadActionURL" name="fileUploadActionURL"></portlet:actionURL>

<form action="<%=fileUploadActionURL.toString() %>" method="post" enctype="multipart/form-data" >
<input id="my_file_element" type="file" name="<portlet:namespace />upload_file" />
<input type="submit" name="submit" value="Submit" />
</form>


ACTION :
========
public void processAction(ActionRequest actionRequest,
ActionResponse actionResponse) throws IOException, PortletException {

UploadPortletRequest uploadRequest = PortalUtil
.getUploadPortletRequest(actionRequest);
File file = uploadRequest.getFile("upload_file");
String fileName = uploadRequest.getFileName("upload_file");




String[] splitString = fileName.split("_");


city = splitString[0];
location = splitString[1];
category = splitString[2];
sub_category = splitString[3];
String imageType = splitString[4];
String extension = splitString[5];

try {
ThemeDisplay display = (ThemeDisplay)actionRequest.getAttribute(WebKeys.THEME_DISPLAY);
User user = display.getUser();
long userId = user.getUserId();
Group group = GroupLocalServiceUtil.getGroup(display.getCompanyId(), GroupConstants.GUEST);
ServiceContext serviceContext = new ServiceContext();
serviceContext.setScopeGroupId(group.getGroupId());

//IGFolder cityIGFolder = IGFolderLocalServiceUtil.addFolder(userId, 0, city, "", serviceContext);

//IGFolder locationIGFolder = IGFolderLocalServiceUtil.addFolder(userId, cityIGFolder.getFolderId(), location, "", serviceContext);



IGFolder categoryIGFolder = IGFolderLocalServiceUtil.addFolder(userId, 0, category, "", serviceContext);
long categoryIGFolderId = categoryIGFolder.getFolderId();
IGFolder subCategoryIGFolder = IGFolderLocalServiceUtil.addFolder(userId, categoryIGFolderId, sub_category, "", serviceContext);


if("small".equalsIgnoreCase(imageType)){
System.out.println("SMALL IMAGE");

IGFolder smallIGFolder = IGFolderLocalServiceUtil.addFolder(userId, subCategoryIGFolder.getFolderId(), "SMALL", "", serviceContext);
System.out.println("small image folder id : "+smallIGFolder.getFolderId());
IGImageLocalServiceUtil.addImage(userId, group.getGroupId(), smallIGFolder.getFolderId(), fileName, "", file, "image/jpg", serviceContext);

} if("medium".equalsIgnoreCase(imageType)){
System.out.println("MEDIUM IMAGE");
IGFolder mediumIGFolder = IGFolderLocalServiceUtil.addFolder(userId, subCategoryIGFolder.getFolderId(), "MEDIUM", "", serviceContext);
System.out.println("Medium IG Folder ID :"+mediumIGFolder.getFolderId());
IGImageLocalServiceUtil.addImage(userId, group.getGroupId(), mediumIGFolder.getFolderId(), fileName, "", file, "image/jpg", serviceContext);

}if("big".equalsIgnoreCase(imageType)){
System.out.println("BIG IMAGE");
IGFolder bigIGFolder = IGFolderLocalServiceUtil.addFolder(userId, subCategoryIGFolder.getFolderId(), "BIG", "", serviceContext);
System.out.println("Big IG Folder ID :"+bigIGFolder.getFolderId());
IGImageLocalServiceUtil.addImage(userId, group.getGroupId(), bigIGFolder.getFolderId(), fileName, "", file, "image/jpg", serviceContext);

}

} catch (Exception e) {
e.printStackTrace();
System.out.println("Exception in try");
}
}


PLEASE GIVE SOME SUGGESTIONS

[Jitendra Rajput, módosítva 11 év-val korábban]

Every time you are trying add new folder with the same name using

 IGFolderLocalServiceUtil.addFolder

.

What you can do is you can create required folders manually . And can get reference to created table by using their names .

  igFolder = IGFolderLocalServiceUtil.getFolder(groupId, 0, folderName);

[Jitendra Rajput, módosítva 12 év-val korábban]

Name of the uploaded file will be change ...that thing you have to manually take care ...

[Vishal Panchal, módosítva 11 év-val korábban]

Hi,

This is good example of doing the same but using service.xml
link--> http://vforliferay.blogspot.in/2010/12/fileupload-using-servicexml-file.html


Thanks & Regards,
Vishal R. Panchal