Struts portlet

[mohammad azaruddin，修改在10 年前。]

Hi

In normal MVC portlet we can hit perticular method using this snipplet
myActionURL.setParameter(ActionRequest.ACTION_NAME, "myMethod");

How can achiev same in struts portlet.
<portlet:actionURL var="myActionURL">
<portlet:param name="struts_action" value="/sample_struts_liferay_portlet/subscribe" />
</portlet:actionURL>
this actionURL hit the processAction method of class defined in struts-config.xml.But i wanted to hit perticular method (myMethod in this case)

How can i achieve this

Azhar
Thanks in advance

[mohammad azaruddin，修改在10 年前。]

Hi all

Is it possible .....?

[Vilmos Papp，修改在10 年前。]

<portlet:actionurl name="myFunction" var="myFuncionURL" />

[mohammad azaruddin，修改在10 年前。]

Hi
Vilmos Papp

Thank you
This is what i was looking for And in sample-struts-portlet all methods are overridden method.so i dont think they used this approach

[Apoorva Prakash，修改在10 年前。]

mohammad azaruddin:

Hi

In normal MVC portlet we can hit perticular method using this snipplet
myActionURL.setParameter(ActionRequest.ACTION_NAME, "myMethod");

How can achiev same in struts portlet.
<portlet:actionURL var="myActionURL">
<portlet:param name="struts_action" value="/sample_struts_liferay_portlet/subscribe" />
</portlet:actionURL>
this actionURL hit the processAction method of class defined in struts-config.xml.But i wanted to hit perticular method (myMethod in this case)

How can i achieve this

Azhar
Thanks in advance

Hello Azhar,

The way you are trying to achieve this, I am afraid this is not possible.

Instead of MVCPortlet, you shout try extending Apache Strut's Action class. See the following class blueprint:

import org.apache.struts.action.Action;
import org.apache.struts.action.ActionForm;
import org.apache.struts.action.ActionForward;
import org.apache.struts.action.ActionMapping;

public class SampleAction extends Action {

	public ActionForward execute(
			ActionMapping mapping, ActionForm form, HttpServletRequest request,
			HttpServletResponse response)
		throws Exception {

			return mapping.findForward("/html/sample/view.jsp");
		}
	}
}

HTH.

Thanks and Regards,
Apoorva Prakash

[mohammad azaruddin，修改在10 年前。]

HI Apoorva Prakash

Thank you for your answer
How if i'm extending Action class and want to jump to perticular custom method....?

[Vilmos Papp，修改在10 年前。]

Probably you could check out our demo struts portlet as well: https://github.com/liferay/liferay-plugins/tree/master/portlets/sample-struts-liferay-portlet

[mohammad azaruddin，修改在10 年前。]

Hi
In sample sturts portlet example renderURL is created using this sniplet

<a href="<portlet:renderURL><portlet:param name="struts_action" value="/sample_struts_liferay_portlet/x" /></portlet:renderURL>">Render</a>

And as mentioned in struts-config.xml it is going to action class

<action path="/sample_struts_liferay_portlet/x" type="com.liferay.samplestrutsliferay.struts.action.XAction">
<exception key="error.sample.exception" type="com.liferay.samplestrutsliferay.SampleException" path="portlet.sample_struts_liferay_portlet.sample_exception" />
<forward name="portlet.sample_struts_liferay_portlet.x" path="portlet.sample_struts_liferay_portlet.x" />
</action>

So my doubt is can we render,Without going to action class....?And without overidding render method of action class,
return mapping.findForward(
getForward(
renderRequest, "portlet.sample_struts_liferay_portlet.x"));

[Apoorva Prakash，修改在10 年前。]

mohammad azaruddin:

Hi
In sample sturts portlet example renderURL is created using this sniplet

<a href="<portlet:renderURL><portlet:param name="struts_action" value="/sample_struts_liferay_portlet/x" /></portlet:renderURL>">Render</a>

And as mentioned in struts-config.xml it is going to action class

<action path="/sample_struts_liferay_portlet/x" type="com.liferay.samplestrutsliferay.struts.action.XAction">
<exception key="error.sample.exception" type="com.liferay.samplestrutsliferay.SampleException" path="portlet.sample_struts_liferay_portlet.sample_exception" />
<forward name="portlet.sample_struts_liferay_portlet.x" path="portlet.sample_struts_liferay_portlet.x" />
</action>

So my doubt is can we render,Without going to action class....?And without overidding render method of action class,
return mapping.findForward(
getForward(
renderRequest, "portlet.sample_struts_liferay_portlet.x"));

Yes, we can do.

You are probably using renderURL and ActionURL wrong.
ActionURL - forwards your request to processAction()
RenderURL - forwards your request to doView()

You should not add the the struts action in renderURL, but in action URL.

HTH

[mohammad azaruddin，修改在10 年前。]

Hi apoorva
In example portlet they were using same param name&value for creating renderURL as well as actionURL.

sample-struts-liferay-portlet example portlet they use
<a href="<portlet:renderURL><portlet:param name="struts_action" value="/sample_struts_liferay_portlet/x" /></portlet:renderURL>">Render</a>
sniplet to create renderURL..You can find sample portlet here

<a href="<portlet:actionURL><portlet:param name="struts_action" value="/sample_struts_liferay_portlet/x" /><portlet:param name="x_param" value="bad_x_value" /></portlet:actionURL>">Action</a>

[Apoorva Prakash，修改在10 年前。]

mohammad azaruddin:

HI Apoorva Prakash

Thank you for your answer
How if i'm extending Action class and want to jump to perticular custom method....?

Hey Azhar,

All the rules of Struts Portlet applies here. But if you are looking for jumping on particular function then you can create portlet with multiple actions as suggested by Vilmos Papp.
You can seek some help from here and here.

HTH.

Thanks and Regards,
Apoorva Prakash

[mohammad azaruddin，修改在10 年前。]

Hi Apoorva Prakash

Thank You the article is helpful

[Apoorva Prakash，修改在10 年前。]

mohammad azaruddin:

Hi Apoorva Prakash

Thank You the article is helpful

Welcome Azhar...